MCAT® ExamChemical and Physical Foundations of Biological SystemsMedium

A pharmaceutical company is developing a new drug that is a weak base. To optimize its absorption in the small intestine, which typically has a pH of 7.4, what characteristic of the drug would be most desirable?

  1. AA pKa value that makes the drug fully ionized at pH 7.4.
  2. BA pKa value close to 7.4.
  3. CA pKa value significantly higher than 7.4.
  4. DA very low pKa value.
Show answer & explanation

Correct answer: C. A pKa value significantly higher than 7.4.

For optimal absorption of a drug, it should be in its unionized (nonpolar) form, as this form can more easily cross lipid membranes. For a weak base, the unionized form (B) predominates when the pH of the environment is higher than its pKa. Therefore, for a weak base to be significantly unionized at pH 7.4 (small intestine), its pKa should be significantly higher than 7.4. This ensures that a substantial portion of the drug exists as the unionized free base (B), which is more lipid-soluble and absorbable.

Why the other options are wrong

  • A. Being fully ionized would mean very poor absorption across lipid membranes.
  • B. A pKa close to 7.4 would mean a significant portion of the weak base is ionized (protonated) and un-ionized, reducing overall absorption compared to a higher pKa.
  • D. A very low pKa would mean the weak base is mostly protonated (ionized) at pH 7.4, hindering absorption.

Drug Absorption and pH

The absorption of weak acid and weak base drugs across biological membranes is highly dependent on their ionization state, which is influenced by the pH of the environment and the drug's pKa.

  • Unionized (nonpolar) forms of drugs are generally more permeable across lipid membranes.
  • For weak acids: Unionized form (HA) predominates when pH < pKa.
  • For weak bases: Unionized form (B) predominates when pH > pKa.

Memory trick: Unionized Unlocks Uptake.

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