A driver is transporting a single, large concrete pipe on a flatbed trailer. The pipe is 10 feet long and weighs 12,000 pounds. It is placed horizontally across the trailer. What is the minimum number of tiedowns required if no chocks or cradles are used?
- A4 tiedowns
- B3 tiedowns
- C5 tiedowns
- D2 tiedowns
Show answer & explanationAnswer & explanation
Correct answer: A. 4 tiedowns
For cylindrical articles such as pipes, when not transported in a cradle or bunk, FMCSA regulations (393.120(c)) require specific securement. For articles with a diameter greater than 1.12 meters (44 inches) and weighing more than 1,100 lbs (which a 12,000 lb concrete pipe certainly is), a minimum of two tiedowns must be used to prevent rolling, and an additional two tiedowns (total of four) must be used to prevent forward and backward movement. Given the pipe is 10 feet long and 12,000 lbs, it falls under the 'heavy and long' category, which also defaults to 4 tiedowns.
Why the other options are wrong
- B. Incorrect. Three tiedowns are not specifically mandated for this scenario.
- C. Incorrect. Five tiedowns would be an over-securement for this specific scenario according to minimum regulations.
- D. Incorrect. Two tiedowns are insufficient for preventing both rolling and longitudinal movement for a heavy, unchocked pipe.
Securing Cylindrical Articles (No Cradles)
Heavy cylindrical articles (pipes, rolls) not secured in cradles or bunks require specific tiedown configurations to prevent rolling and longitudinal movement.
- Minimum of 2 tiedowns to prevent rolling.
- Additional 2 tiedowns to prevent forward/backward movement (total 4).
- Tiedowns must be placed to provide maximum securement.
- Applies to items over 1,100 lbs and large diameter.
Memory trick: Heavy pipe, no cradle, four straps to keep it stable!