FAA Aviation Mechanic General (AMG)Physics, Math and Fluid LinesMedium

A confined gas in a rigid, sealed hydraulic accumulator has a pressure of 50 psia at a temperature of 60°F. If the container cannot expand and the gas is heated to 160°F, what is the new pressure (assume constant volume)?

  1. A59.6 psia
  2. B67.3 psia
  3. C45.2 psia
  4. D50.0 psia
Show answer & explanation

Correct answer: A. 59.6 psia

This is Gay-Lussac's Law: P1/T1 = P2/T2, using absolute temperature in Rankine (°F + 460). T1 = 520°R, T2 = 620°R. P2 = 50 × (620/520) = 59.6 psia.

Why the other options are wrong

  • B. This value results from using Fahrenheit temperatures directly instead of Rankine.
  • C. This results from dividing instead of multiplying the temperature ratio.
  • D. This ignores the temperature change entirely, assuming constant pressure.

Gay-Lussac's Law

For a fixed volume of gas, pressure is directly proportional to absolute temperature: P1/T1 = P2/T2.

  • Volume must remain constant
  • Temperature must be converted to absolute scale (Rankine or Kelvin)
  • Used to predict pressure changes in sealed containers when heated

Memory trick: 'Pressure follows heat when volume can't retreat' — Gay-Lussac's rule.

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